The dimension of P = frac{B^2 l^2}{m} is,wher | vedclass

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(B) The magnetic force is given by $F = BIL$,where $B$ is the magnetic field,$I$ is the current,and $L$ is the length.Therefore,the dimension of $B$ i

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$ML^2T^{-4}I^{-2}$

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(B) The magnetic force is given by $F = BIL$,where $B$ is the magnetic field,$I$ is the current,and $L$ is the length.Therefore,the dimension of $B$ is $[B] = \frac{[F]}{[I][L]} = \frac{[MLT^{-2}]}{[I][L]} = [MT^{-2}I^{-1}]$.Now,substitute the dimensions into the expression for $P$:$[P] = \frac{[B]^2 [l]^2}{[m]} = \frac{[MT^{-2}I^{-1}]^2 [L]^2}{[M]}$.$[P] = \frac{[M^2 T^{-4} I^{-2}] [L^2]}{[M]}$.$[P] = [ML^2 T^{-4} I^{-2}]$.

The dimension of $P = \frac{B^2 l^2}{m}$ is,where $B = \text{magnetic field}$,$l = \text{length}$,$m = \text{mass}$.

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